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¡‚©[‚Æ -2021/12/22 (Wed) 07:33
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‚±‚ñ‚É‚¿‚ÍB(1) ç[0,1]x^2dx + ç[1,2]{(x-1)^2+1}dx = [x^3/3][0,1] + [(x-1)^2/3 + x][1,2]‚ ‚Æ‚ÍŒvŽZ‚·‚邾‚¯‚Å‚·B (2) ç[0,ƒÎ]sinxdx = [-cosx][0,ƒÎ]‚ ‚Æ‚ÍŒvŽZ‚·‚邾‚¯‚Å‚·B (3) ç[0,ƒÎ](1+cos2x)dx = [x + (1/2)sin2x][0,ƒÎ](4) ç[-1,1]{1/ã(1-x^2)}dx = 2ç[0,1]{1/ã(1-x^2)}dxx=sint ‚Æ‚¨‚ dx=costdt x:-¨1 ‚ɑ΂µ t:0¨ƒÎ/2—^Ž® = 2ç[0,ƒÎ/2]{cost/ã(1-sin^2t)}dt = 2ç[0,ƒÎ/2]{cost/cost}dt = 2ç[0,ƒÎ/2]dt = ƒÎ
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¡SB -2021/12/22 (Wed) 10:05
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